Math and Science Tutor
Student, 3 years of experience of tutoring
The best way to learn math is to actually understand it. Research shows that then you learn 9 times better.
How would you solve this problem?
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Warm welcome to everyone who is interested in our webinar where we will discuss how to cope with exam stress and a balance between school and personal life. Message us to reserve your place!✅
Day: Saturday 11 November
Time: 2pm (GMT)
Euler's identity is e^(πi)=-1. Indeed, on an Argand diagram a complex number with argument π radians is -1.
But this also means that πi=ln(-1), and so 2πi=2ln(-1)=ln(1)=0. How is that possible?
We need to remember that we have 2π radians here, which is the same as 0 radians. It is not the plain number 2π. This is what may cause confusion.
21/10/2023
Dear all,
I am delighted to present our new logo. Our tutoring services are upgrading soon!
What will change?
- New website interface
-Interactive whiteboard
-Pay online conveniently
-New Google Classroom system
And much more! Please check out regularly so that you don't miss the latest updates!
01/10/2023
We have arrived to this wonderful place... as we say, math works best with a clear mind🌳
16/09/2023
Update announced!
Now it will be even easier to book lessons! Our new chatbot https://t.me/mathandsciencetutor! Check it out!😁
In the book "Alive Mathematics" of the famous mathematician Yakov Perelman (chapter 1), the writer talks about what "making a loop" may mean.🤔
He gave 2 scenarios: making a loop around a tree with a squirrel sitting on it, with the squirrel being stationary. In this case, we can tell that we are making a loop based on the fact that we can see the squirrel from different orientations. We can see its head, its tail, and from the side. ⬅️↖️➡️↘️However, what if the squirrel keeps turning towards us, while we are going around the tree? We cannot see the squirrel from all sides - only its head. Does it mean that we did not make a loop? Or it still does, because we are again making a circular motion?🐿️ Think about this, and the answer will be in the comments :)
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